H Algebra 2 Trig ch. 9

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H Algebra 2 Trig ch. 9

2/18/2011

Happy Blogging!

Archana Sathappan

2/20/2011 04:14:02 am

For pg. 494, is number 6 a hyperbola? And number 12 a parabola? i just want to make sure I'm doing this right.

Ishta

2/22/2011 07:00:27 am

Yes, you are right. On number 6, the variables are squared and the coefficients and signs are different, hence a hyperbola.

Ishta

2/22/2011 07:01:19 am

When I say different I mean opposite. It was a bit unclear. Sorry.

Randy Boyd

2/22/2011 10:30:57 am

if you have the vertices and foci of an ellipse, how do you find the radius of the minor? i understand that the vertices will tell you the center and the radius of the major. but i couldn't figure out the radius of the minor.

Ashley Bruner

2/22/2011 11:49:55 am

Randy: i believe that u do a(major)^2-b(minor)^2= c(foci)^2. so if you plug in the major axis and the foci for a and c you should be able to find the minor axis. I'll check on that to make sure though

Archana Sathappan

2/25/2011 08:33:12 am

When doing systems of equations, do we need to find the foci, vertices, asymtopes, etc for each seperate conic? Or, do we just need to find the points of intersection?

Archana Sathappan

2/25/2011 08:40:44 am

Is the answer to number 12 on pg. 503 no solution?

Ishta

2/26/2011 12:32:40 am

Arachana, I had the same question so I asked others and they also said no solution.However, this is not a confirmation. Is there anyone who knows the answer to number 12?

Christian Carvallo

2/27/2011 04:10:13 am

Archana to answer you question whether we find the foci, vertices, asymtopes, etc for systems of equations, we do not have to. All the book asks for is to find the points of intersection and graph the conics to make sure your points are correct.

Rohan

2/27/2011 08:25:37 am

How do we do problem 23 on pg 504.
Im not sure if we complete the square for x, or isolate the 9 and bring over the y.
Also, do you have to square the bottom part which is x-y=3

Nadia Fayoumi

2/27/2011 09:27:28 am

Rohan:
For page 504 problem 23 I solved it by doing the following steps:

First, I changed the second equation to y=x+3
After doing this, I set the equations equal to each other.
x^2+8x+9=x+3 (I did this because it is another way of solivng systems without needing to use the elimination process)
After I did this I set the equation equal to 0. Which looks like : x^2+7x+6=0
Once you do this then you can factor the equation. The result is (x+6)(x+1).
So x=-6 and x=-1
Then I plugged these answers into one of the original equations. I got y=-3 for x=-6. I got y=2 for x=-1.
So my final coordinate points are (-6,-3) and (-1,2)
-The graph should have one straight line and one parabola

Archana Sathappan

2/27/2011 10:15:49 am

For the equations of the aymptotes of hyperbolas, do we need to include x or y=? If so, how do we know if it is x or y=?

Zain Rahman

2/27/2011 10:45:18 am

How would you find the conic for number 13 on pg 504?

Archana Sathappan

2/27/2011 11:30:03 am

@ Zain
The first equation in number 13 is a circle b/c both terms are squared, the coefficients are the same, and the signs are the same. The second equation is a ellipse b/c both terms are squared, the coefficients are different, and the signs are the same.
To find the intersection point, I believe that you would need to isolate the second equation in terms of y= and substitute that in for y in the first equation.

Emma

2/27/2011 01:21:01 pm

Archana- We've never been asked to find the equations of the asymptotes of hyperbolas on homework so I would assume we wouldn't need to for the test. But if so, you could find it like a regular linear line so y=mx+b. Just putting +- the slope I think would be fine :)

Erin Hohman

2/27/2011 02:32:26 pm

I'm confused for the problems on pg 503 number 3 how to graph the two equations?

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H Algebra 2 Trig ch. 9

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