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Hello Classmates! Feel free to post your questions and answers here. Teamwork is beautiful!
Mrs. Johnson's 20152016 BC Calculus Students ROCK!
Archana Sathappan
11/19/2010 09:21:06 am
For the homework Pg 339 #3c, it asks for the removal discontinuity after graphing. I graphed it and I understand how to find the hole/removal discontinuity for only the x portion. How do I solve for the y portion of the hole/removal continuity. I got that the x hole is 2. In the back of the book it says that the removal discontinuity is (2,2). So, the y portion of the hole is 2 as well. But, how do you find that?
craig cook
11/21/2010 07:45:00 am
for #52 p.334 i cant seem to factor it even though it is probably somthing really simple
Nikita Hariharan
11/21/2010 08:35:31 am
#52.
Johannes Grandin
11/21/2010 10:42:40 am
Just wondering how to factor number 19 on page 340.
Johannes Grandin
11/21/2010 10:45:26 am
For page 339 #3c, you can actually just plug it into the calculator and then look at your graph. Then you can go to your table and wherever it says ERROR for the y portion, that's the hole. The hole is also whatever you were able to cancel out when you factor the numerator and denominator.
Miranda Colin
11/21/2010 11:01:59 am
On page 340, how do you factor #53 and #61? For #61, I have a feeling it has something to do with the difference of two squares but I can't figure it out.
Johannes Grandin
11/22/2010 08:35:35 am
Hey I was just wondering if the quiz tomorrow is just on 7.3 and 7.4 or also on any other sections?
Ayo Adewole
11/22/2010 09:25:40 am
Can someone please do number 78
Ayo
11/22/2010 09:27:55 am
Kirin Upadhyay
11/22/2010 09:48:40 am
for number 6 on page 360 would the answer to the problem be x cubed + ll x squared +40x because there was a 48 in the polynomial but since it was divided by 48 wouldn't that just be one?
Kirin Upadhyay
11/22/2010 09:50:06 am
oh, wait couldn't you just cancel out the 12 and the 4 in both equations then? yea nevermind
Nikita Hariharan
11/22/2010 09:55:56 am
Ayo:
Ishta
11/22/2010 10:12:23 am
On P341, what is the best way to solve question number 47? Also, how would you solve question 58 on the P334?
Zach Zielke
11/22/2010 11:15:12 am
On page 339, how would you do number 17? I just need help with one and I can do the rest, thanks.
Christian Carvallo
11/22/2010 11:21:50 am
Christian Carvallo
11/22/2010 11:23:50 am
Zach the answer to 17 would be
Ashley Bruner
11/22/2010 12:40:02 pm
How would you do #86 on page 333? I don't understand how you break down the square in this problem
Ritika Rao
11/22/2010 01:05:29 pm
Can somebody explain #85 on 333? I know it breaks down into [6(x5)][6+(65)] but I don't get how to get the "[6+(65)]" part of it.
Becky Wegner
11/22/2010 01:16:43 pm
Can someone help me with number 5 on tonights homework which was page 346?
Aneesh Asokan
11/23/2010 09:33:41 am
When you do long division, how do you know when to make subtraction or addition in the answer??
Archana Sathappan
11/23/2010 12:29:11 pm
Aneesh You just have to change the sign of every variable/constant of whatever the remainder is.
NIkita Hariharan
11/24/2010 01:39:02 am
Pg. 333
Nikita Hariharan
11/24/2010 01:40:51 am
Pg. 333
Nikita Hariharan
11/24/2010 01:53:25 am
The answer for #5 on pg. 346 is x^2 x+3.
Nikita Hariharan
11/24/2010 01:56:52 am
Oh and sorry Becky for the signs you always change the sign to whatever the constant/variable is. so for exaple, in the problem you asked, when there is a remainder of 2x squared +7, the first term is negative so the number you would plug in would have to get you to a negative that way when you subtract, the terms will cancel out.
Ishta
11/24/2010 02:07:15 am
Beckythe question is 2x^33x^2+7x3/(2x1). first take the 1st 2 terms, 2x^33x^2 and look at the 1st one. 2x^3 divided by 2x (from 2x1)That would be x^2 so put that at the top of the radical. Then multiply x^2 and 2x1. That should equal 2x^3+x^2. Then subtract it from the the orginal(2x^33x^2). DO NOT FORGET TO CHANGE SIGNS. That will you with 2x^2. Bring down the 7x. Now think again, 2x^2 divided by 2x=x. Put negative above the radical. Multiply through and subract. You should be left with 6x. Bring down the 3. 6x divided by 2x is 3 so put that on top of radical. Multiply through and subtract. There should be no remainder. The answer is (2x1)(x^2x+3)=2x^33x^2+7x3. Check answer by distributing and you are done.
Jelena Martinic
11/28/2010 05:02:37 am
I don't have my book with me and I’m not sure if I copied the problem wrong, but i can't seem to factor #54 on pg.333?
Emma Burck
11/28/2010 06:20:52 am
Jelena The problem was 6x^2+37x20.
Emily Cowgill
11/28/2010 02:04:07 pm
I can't seem to factor number 54 on pg. 334, could someone please help me out?
Hayley Vaughn
11/28/2010 03:18:20 pm
Does anyone know how to do number 59 on pg. 341 or number 1 on pg 346?
Ryan Vasicek
11/29/2010 02:17:55 am
@ Emily
Tucker Jacob
11/29/2010 07:15:54 am
i do not understand how to divide number 13 on pg 346. Can anyone explain and show me how to do it step by step
Archana Sathappan
11/29/2010 09:30:43 am
The problem for 13 on pg. 346 is x^3+3x^2+3x+1/x^2+2x+1. First do x^3/x^2 to get x and place that right on top of the x portion of your division set up. Then multiply all the terms (x^2+2x+1) by x to get x^32x^2x. Then change the sign of all of those that you can take the difference of that from x^3+3x^2+3x+1. The remainder is then x^2+2x+1. Then you do x^2/x^2 to get 1 and you place that right on top of the constant portion of your divisiom set up. Then multiply 1 by x^2+2x+1 to get x^2+2x+1. Then change the sign of all of the terms so that you can take the difference of that from x^2+2x+1. The remainder is 0. At the top in your "answer section" you have x+1 as your answer and there was no remainder, so the answer is x+1. Hope this helps!
michelle filipek
11/29/2010 01:14:17 pm
how do you do #39 on page 340?
michelle filipek
11/29/2010 03:08:33 pm
For our homework on page 346 should number 17 have a remainder? and how would you do number 19?
Jacqueline Pedersen
11/30/2010 02:22:46 am
For number 17 on page 346, yes you should end up with a remainder of 2. So your answer would end up like:
Jacqueline Pedersen
11/30/2010 02:33:43 am
For number 19:
Jacqueline Pedersen
11/30/2010 02:41:11 am
#39
Jelena Martinich
11/30/2010 08:05:59 am
Can someone please explain how to solve tonights problems on page 353? I just need one example 'cus once again  i left my book at home and only copied the prbolems :/
Nikita Hariharan
11/30/2010 08:27:32 am
Jelena:
Aneesh Asokan
11/30/2010 09:09:44 am
I just want to make sure, most of the answers for tonights homework i got to only two answers. Not like the one we did in class today. Just want to know if I am going the right way, or if i totally messed up or anything.
Emily Cowgill
11/30/2010 11:43:59 am
Aneesh  I actually got 2 or 3 answers for the ones I found answers to. I'm not sure if I did it right though.
Emily Cowgill
11/30/2010 11:47:03 am
previous cont.
Meltem Cazimi
11/30/2010 11:56:14 am
emily! uhmm no you cant just take an exponent out as a GCF it has to have the same base, you need to look at what you cubed to get the number thats there. for number 37 you have to cube r to get r^3 and you have to cube s^2 to get s^6, so then you do (rs^2)(r^2+rs^2+s^4) because you take and square the first and second numbers in the first perenthesis to get the first and last number in the second and then just multiply those two to get the middle. i hope that makes sense.
Meltem Cazimi
11/30/2010 11:59:05 am
for the first two problems on the homework, numbers 3 and 7, i plugged the equations in the calculater and the graph shows both of them crossing the x axis which means theres a solution, but in the table there are no 0's to indicate which would be solutions, also when i used the factor theroem i couldnt figure out what would be the solutions, help ?
Archana Sathappan
11/30/2010 12:28:33 pm
The way you check to see how many answer you will get is by looking at the highest exponent in the problem. SO if you had something like 2x^3+2x^2+5+1, you would have 3 answers b/c the highest exponent is 3. Hope this helps Aneesh.
craig cook
11/30/2010 01:27:32 pm
Meltem, even though the graph touches the xaxis, the solutions are not integers so that is why none of the numbers equal 0, so u r right about there being no solution. About the other question, when you find which number(s) are equal to 0, take those number(s), flip the sign in front of them and put and x in front of it. Here is an example:
Jordan Crouch
11/30/2010 02:13:49 pm
Alright so on pg 346, number 9, how would you factor that? I got halfway through it and then got lost.
Brandon Jachimiec
12/1/2010 06:41:35 am
@Jordan Crouch
Kayla Mann
12/1/2010 10:16:56 am
For last night's homework on page 353, does anyone know how to solve number 15?
Aneesh Asokan
12/1/2010 11:20:17 am
Hey, I had a quick question on the Homework on page 360 336 by 3s. I don;t get how to do any of them. I Sort of get it but I sorta Don't get it too.
Tyler Yanisch
12/1/2010 11:25:00 am
On page 353, how do solve number
Karthik Makayee
12/1/2010 12:07:26 pm
@Kayla
Ishta
12/1/2010 12:14:21 pm
On page 360, how would you do number 33? Thanks :)
Karthik Makayee
12/1/2010 01:01:05 pm
@Aneesh
craig cook
12/2/2010 08:40:12 am
would anyone know how to do #33 on our 77 homework?
Archana Sathappan
12/2/2010 09:03:47 am
@ Craig:
Rohan
12/2/2010 09:42:42 am
Hey, Can someone just show me the steps me ro problem 27 on page 360 for the 7.7 hw? im gettin the right answer I just dont think I am doing it right.
Amir Khalid Richardson
12/2/2010 10:10:01 am
Rohan to solve for number 27 you should factor it so it is (x+5)(x+8)/(5x)(x+8) after you cancel out the eights you should end up with (x+5)/(5x), which can't be factored
Christian Carvallo
12/2/2010 11:16:23 am
Hey guys I need some help on number
Aneesh Asokan
12/2/2010 11:25:36 am
Hey,Number 33 on Tonight's homework is super confusing. Can someone, by any chance, help me out.
Archana Sathappan
12/2/2010 11:31:15 am
@ Christian
Archana Sathappan
12/2/2010 11:34:03 am
@ Aneesh
Christian Carvallo
12/2/2010 11:39:00 am
Thank you archana
Dan Casey
12/2/2010 11:59:40 am
Pg. 360 #30, does the sum of the two cubes cancel out the (x^2 2x +4)?
Zain
12/2/2010 12:16:26 pm
What is the answer to number 12 on page 360?
Archana Sathappan
12/2/2010 01:01:16 pm
@ Zain
Michelle filipek
12/3/2010 05:30:01 am
how would you do #33 on page 360?
Archana Sathappan
12/3/2010 08:56:29 am
@ Michelle
Johannes Grandin
12/4/2010 05:10:07 am
How would you do number 44 on page 362. It is giving me some trouble.
Ishta
12/4/2010 08:28:51 am
Thanks Archana for answering my question.
Noelle Linden
12/5/2010 04:41:30 am
Hey, i was wondering if someone could explain how to do number 48 on page 362 for the 7.7 homework?
Ashley Bruner
12/5/2010 07:43:30 am
Noelle
Miranda Colin
12/5/2010 10:46:00 am
Hold up, sorry Ashley but I'm still kind of confused on #48. In your explanation you canceled out the minor denominators right away but the example in the book didn't. Did someone else do it slightly different than Ashley? And can someone give me an answer to #48 because I have an answer but I'm really unsure if it's right.
raj shah
12/5/2010 01:05:56 pm
okay so for the new way
Ishta
12/6/2010 09:07:34 am
Does anybody know how to do #30 on page 368? Just tell me what I need to multiply.
Ashley Bruner
12/6/2010 09:59:35 am
Could somebody please show me how to do #s 30 and 33 on page 369 from tonights homework?
Melina Kanji
12/6/2010 12:41:59 pm
Can somebody help me with question 18, 30, and 33 from tonight's homework, please?
Johannes Grandin
12/7/2010 02:53:00 am
Ishta, Ashley, and Melina:
Archana Sathappan
12/7/2010 10:59:05 am
Can someone explain how to graph 22 on pg. 376 besides plugging it into the calculator?
Zach Zielke
12/8/2010 08:58:26 am
I do not get at all how to graph any of the problems from 7.9 homework. I've been plugging them into my calculator and taking those graphs but if we can't use our calculators can someone show me how to graph them?
Ryan
12/8/2010 01:43:28 pm
Ryan
12/8/2010 01:46:44 pm
I don't know how to do number 6 on page 376. I got to x3/x+ 1 with a hole of 2 but I don't know what to do from there. HELP!!
Christian Carvallo
12/8/2010 02:20:58 pm
Ryan, for number 6 the coordinates of the hole would be (2,5) you can find that by replacing x with 2 to find the y coordinate. The VASY would be at 1 because if you substitute 1 of x you get zero in the denominator. And the HASY would be at y=1 because both the numerator and denominator have high powers of 2 so by taking the highest coefficient of the two, (they are both 1) you get 1. hope this helps.
Johannes Grandin
12/9/2010 02:42:18 am
Hey I was just wondering if we have gone over 710 already or if we are doing that today (Thursday) in class. I think that's the homework we were supposed to do for today but I'm not sure. Does anyone know???
craig cook
12/9/2010 07:56:53 am
would anyone know how to do #30 on page 381?
Erin Hohman
12/9/2010 10:17:34 am
Can anyone help me out with question #30 from pg.381..i dont understand how to find the x's?
Emily Cowgill
12/11/2010 04:50:34 am
Does anyone know how to reset a TI84 Plus silver edition? i have been trying to do the finals packet and when i plugged in the matrix to find the determinant, it said "error: invalid dim". does anyone know what that means?
Kristina C.
12/11/2010 05:42:42 am
Emily
Zain
12/12/2010 05:03:14 am
What's the equation for number 2 on page 393?
Ashley Bruner
12/12/2010 06:48:40 am
Could someone please tell me how y varies with x in #14 on page 397? I can get the rest of the problem if i know that
Miranda Colin
12/12/2010 10:49:08 am
Ashley, I don't have my book with me because I finished the homework in school so I don't remember what the problem was about. However, from what I understand, if y increases while x decreases, or vice versa, then it's inversely. If both y and x increase or both y and x decrease then it varies directly.I'm not entirely sure if that's what you were asking for so sorry if I didn't answer your question.
Jake Bennema
12/12/2010 12:35:35 pm
FOr #14 on page 397, I am pretty sure for question a, it is an inverse proportion, but I am not sure how to set up the general equation, any help would be great. thanks Comments are closed.

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