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Archana Sathappan
4/19/2011 11:53:12 am
Can someone please help me on number 18 part b and c on pg. 868?
Johannes Grandin
4/20/2011 03:47:14 am
For those draw a triangle first to help you and remember that Wendy walked 101 meters since each pace was one meter.
Ishta
4/20/2011 12:42:04 pm
I tried doing question 18 again, but I still can't solve part b and c. Can someone help? How do I draw the triangle for the two parts. Thanks.:)
Johannes Grandin
4/21/2011 04:01:07 am
Does anyone understand numbers 1, 3, and 7 on last night's 15.2 homework?
Ishta
4/23/2011 08:16:08 am
Johannes,
Johannes Grandin
4/26/2011 03:45:44 am
Thank you.
Archana Sathappan
4/26/2011 11:50:37 am
Can someone please help me on pg. 919 # 13? For part a, I started it out, like they said by splitting it into 2 triangles and for one triangle I got an area of 1560.6 m^2, but I was unable to figure out how to find the area for the other triangle. Any help would be great, thanks!
Ishta
4/28/2011 08:38:12 am
Archana,
Rohan Roy
4/28/2011 08:57:29 am
So whenever you are trying to find a angles, for either right triangles, law of sines or cosines, you always use the inverse button right?
Archana Sathappan
4/28/2011 10:04:35 am
Rohan,
Nikita Hariharan
5/7/2011 04:31:27 am
Ishta:
Nikita Hariharan
5/7/2011 12:02:35 pm
Hey can anybody explain ambiguous cases to me? I understand everything except the ambiguous case for the test.
Rohan Roy
5/8/2011 04:08:08 am
So for the ambiguous case, if you get a degree under 180 then there is only one possibility, and if its over 180 theres no solution, and if it perfectly adds up to 180 then theres 2 solutions. is that right?
Ishta
5/8/2011 09:09:32 am
I agree with you Rohan. To find the ambiguous case, subtract the ambiguous angle from 180. Then, use the given info and see if it is over/under 180 to trell. Does that help, Nikita? Comments are closed.

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