For tonight's homework for problems 18 and 20, i understand how to find the answers using the calculator but i am confused on how to find the answers without one. To start them off i plugged in, for example #18, -1 and 7 into the variable spot. But when i add them up i do not get what i get from using the graph with the calculator. I know i am missing a step or something. Please help.
for numbers 11-20 that we had to do on the homework, when you get the possibilites of the roots, withought using the calculater, how do you find which ones are the answers? do you just plug them all in untill you figure out which ones work ?
i can just show you how i did one of them and see if it helps you.13. X^3 - 7x^2 + 11x + 3I found the first zero by plugging the equation into the calculator and i got 3 or (x-3). I then took the three and used synthetic division with the equation and i got another equation of x^2 - 4x - 1. Then, you do the quadratic equation for x^2 - 4x -1 and i got another zero of 2 plus or minus the square root of 5. i hope this made sense and helps
Meltem:You can use the factor theorem or when you are plugging it in on your calculator and go to the table you can see like the coordinates and it usually gives you atelast one coordinate where it is (x,0).
Meltem:Sorry, this would be a better answer... You could use the factor theorem, then long division or synthetic division (which ever one you prefer) and you may need to use the quadratic equation as well when there is a possibility for imaginary numbers in your answer.
could someone explain to me how to find answers to these polynomial equations without a calculator? i can figure out how to do it with one but am not sure how to do it without the assistance of a calculator, this isn't really a question on a specific problem just a general question about the process, thanks
Can someone help me do problem 36 on tonights homework? When i plugged it into the calculator i got two zeros but i did synthetic division for only one of them and i got confused on how to get the other two numbers from the problem. Thank you!
CAn anyone help me with number 19 on Skills Practice 78 I understand how to do problems like this but I cannot understand problems like this with a complex number, root and real number. Thanks
Could someone please explain how #38 works out from tonight's homework? Also, how is #52 (a sketch graph) possible?
Can someone please help me with number 20 on page 540?
@AshleyFor number 38, I think you can just use the factor theorem to figure that one out. I'm not sure on number 52 though.
For the section on the worksheet that says "solve over the set of complex numbers" i'm doing the quadratic equation like it says in the book but i'm getting fractions and real numbers instead of complex numbers. Is using the quadratic equation the correct way or am i missing one part of doing the problem?
How would you do number 38 on pg 540?
To Kirin:I believe you are doing the worksheet correct. When I solved those problems, I would not get complex numbers but instead my solution would be something like 1 + or - .2 making the solutions .8 or 1.2. The solution is correct, it just isn't complex.To Jordan C.For number 38, you would use the factor theorem (Factors of constant/ Factors of leading coefficients) then plug that in. You simply have to do this until it works. With that solution, you would use synthetic division, to get the remaining equation, then from their you can do synthetic division again. The roots ed up being -4,-1 (double root), and 2.In addition, you can always check your solution by graphing on your calculator.
On the world problems, on page 554, #3 and 5, when finding the a,b,c,d variables,, do we use the matrix way or is there an easier way to do it? Is it the right to do it?
To Ishta,To find the variables:Are you asking how you use your calculator to find the equation? If so the steps are:press STATEditGo to List (make sure they are clear)plug in the x and y termspress 2nd quitthen press 2nd y=hit entermake sure it is turned to onTo see the data then press zoomgo down to #9 zoom stathit enterThen press STAT againgo to Calchit #6 cubigreghit 2nd 1(L1)hit ,hit 2nd 2 (L2)hit ,they press VARSgo to Y VARShit functionpress y1Ok these are the steps! I hope that I answered your question right!
Can someone explain part d on problem 3 pg 552? I think the answer is no...but, I'm not sure.
Archana, the answer is yes, because if you did the calculator steps and did the ask button to see the points, 700 degrees can make the viscosity 0.
Will the stuff we learned in class today be on the test tommorow if so where can i find examples to do?And will someone explain to me how to do number 3 on the green colored quiz
@Zachthe examples we did today will be on the test, or similar ones to it because she said earlier that however you do on the review is how you'll do on the test or something along those lines.Also could some one tell me if an imaginary number could be negative because there is a review question in the book that states -(square root)of -3. thanks
Just making sure, when graphing imaginary numbers, the x-axis is the real numbers (a)and the y-axis becomes the imaginary line (bi), right? I just want to make sure.
Ishta,Yes: x is the real-axis and y is the imaginary-axis.
for cubic regression, if the x values are in the thousands ex. 24,000 and you enter it in list one as 24 would you also have to divide your y values by 1,000?
Did you guys get 10,000 dollars for your answer on the test if no trailblazers were to be manufactured each month?
Can someone help me with pg. 416 number 5 part e and f?
I actually got part e and f. I need help only on part h. Can someone help me out, please?
Thank You Mrs. Johnson! Archana, #5 part h I think is that the value for x is the same as minimum value. Does that answer your question?
The blog spot is soooo helpful.
Last night when I was working on math, I couldn't figure out Pg. 416 #5 e and f - I understood what it was asking but none of the answers I got made any sense... any suggestions?
Emma,I had a hard time with those at first too, but then I finally got them after I thought about it for a while. Ok, so I'll start you off. Once you set up your equation, so with part e it would be -5= x-3(square root of x+4), the first step would be to subtract x from both sides and then divide both sides by -3. Then, you will be left with -5-x/-3= square root of x+4. Then sqaure both sides to get rid of the square root. Then, it's similar to what we've worked with before. Hope this helps!
Mrs. Johnson teaches math at Metea Valley High School in Aurora, IL.
Ap Ab Calculus
H Algebra 2 Trig
H Pre Calculus
Regular Pre Calculus