How do you do the homework with radicals if there are 2 separate radicals? I know in the book it says to isolate one and then square it but I don't understand how they ended up with the equation they show after that.
You either multiply by the conjugate to get rid of the radical or multiply the radical by itself to get a plain number. If there is a partical number you need help with I might be able to help you a little bit more. Hope this helps!
So if there is one radical on the bottom, and another one ontop, both seperated by a subration sign, do you need to mutliply both part by the conjugate? Im looking at number 6 on page 421
Rohan, i'm pretty sure you only multiply the first one by the conjugate and leave the problem after the subraction sign alone.
To Rohan:Heres what I didFor number 6 on page 421, i multipled the first fraction by 5 root 3 in order to get a whole number on the bottom. When you multiply the top and bottom by 5 root 3 you get 35 root 3/ 75. Then you multiple the second fraction by 5 over 5 so both denominators are 75. Then you subtract root from root to which reduces to root over .
If you had something like f(x)= the sqaure root of (0.5x), would the transformation be half the domain?
Archana, I would think thats how you do it. I'm not sure though.I have a question, does anyone know how to do #13 on pg 428? I keep getting some strange answer (aka x=x^2). And #19 on the same pg, I got another strange answer. Does anyone know how to do those?
Archana, I don't think so. You are SQUARING it which I don't think is HALFING it. My question is on page 428, number 35. I found an answer but I think I am doing my own creative math.
for #19 you subtract 3 again to get the square root of 3x-11=x-3then you square both sides and get 3x-11=x2-6x+9 and when combined with 3x-11 equals x2-9x+20 which factors out to x= 4 and 5
How do you do number 35 on page 429?
Hey does anyone know how to do number 32 and 34 on the homework tonight i tried them both numerous ways but cannot get the right answer, thanks
Christian,For number 32, I got no solution as my answer. I don't think we had to do 34, so I'm not sure for that. Sahana,Number 35: Subtract the last term from both sides to get 0 on one side. Then multiply the second and third terms by their conjgates. Combine like terms and you should end up with 1-2(square root of x)/1-x=0. Multiply by 1-x on both sides to get rid of the denominator. You are left with 1-2(square root of x)=0. Add one to both sides and thn divide by 2. You get that the square root of x=1/2. So, that means that x=1/4. Plug it into the original equation to see if it is an extraneous solution o if it is a solution. In this case it is. So, 1/4 is your answer. Hope this helps!
hey, just wondering how to do letter C number 3 on the 8-5 homework. thanks
To Craig:For #3 C, i plugged 6700 (the length) into my equation for the y. This is what my equation looked like:6700 = 1.155 X A^0.6 (where A is area of the basin). I divided both sides by 1.155 to get A^0.6 = 6008.96 then I raised both sides to the 10/6 to get A^1. So it is 6008.96 ^10/6 which equals 1986094.42 sq kilometers. Hope I helped.
Brandon, why did you put the area to the 0.6 power? I thought it was extra information...unless I read the problem wrong...
Miranda,The 0.6 was not extra info. If you look at the examples in the book, they show you how to set up the equation when given a non integer exponent.
Brandon, would doing both sides ^0.6 make the area 1? I thought if it was ^0.6 on one side to get the area to equal one you would raise the sides by ^0.4...
Since 0.6 = 3/5 and you are trying to get rid of radical on x, you must raise everything to the 5/3 power to get the x alone and then you can divide to get the value for x.
by radical i meant exponent ^^^
Hey, for the word problems homework on page 446,I really don't know how to set up the equations.
I am pretty confused on the word problems. I don't know how to set them up. I get really confused while doing them. Especially the ones on Pg. 446.
Can i get some help on #11 on page 450. thanks
Hey guys i'm really confused with number 9 on page 446. Help, please!
How would you solve R3 on page 453 in the review section? especially letter d. Thanks
Does anybody know how to do number 3 on pg 446? I'm so confused!!
Karishma- for 446 #3
What I did first was set up two basic 2-variable equations for pressure and width of the heel and then another one with pressure and weight so I could just see the inverse and direct proportions separately.
P=kw --> w being width and p being pressure
P=k/h^2 --> h being heel width
Then I combined the two equations to get P=(kw)/h^2
After that all you have to do is plug in the numbers they give you in the problem to the separate variables and you should get the value of the constant :)
can someone help me with number 8 on page 449? thanks!
Jordan for page 453 R3 D first you multiply the denominator by a number that works perfectly with the 1/5 root. In this case it would be 81 to the 1/5 root. After you do this you get 243 to the 1/5 root which is 3. Then you have to multiply the numerator by 81 to the 1/5 also which gives you 3 and 81 raised to the 1/5 root. The 3s cancel and you get 81 raised to the 1/5
For the problems that Mrs. Johnson gave us in class. On 5d, what do you do after multiplying the numerator and denominator by √x and then by it's conjugate.
in the review problems she gave us, the one where you have to graph the problem, for letter f. find the function value where f(x)=-3 you would just set the equasion equal to -3 right?
how would you do number 9 on page 449?
i don't understand part B in the last part of the review problems, -y square root 18x^2y + 5x square root 2y^3. i know you have to get like terms but how?
Michelle for the review problem, yes you would set the equation to -3 because f(x) is the same thing as y. So if f(x) equals -3, then y=-3.
Dan Casey: on number 5d after you multiple the numerator and denominator from its conjugates you get the answer x+2 square root x +1/ x-1. Then this is your final answer because it cannot be simplified any further.
hey say you have two radicals in an equation, after isolating one radical and squaring both sides, do both the radicals disappear, or do you foil one of them, or foil both of them?
no, only one of the radicals will end up disappearing, after you get rid of the first radical you isolate you must then re-isolate the second radical that you moved to one side or the other of the equation and start over. after you do it a second time (if you only have 2 radicals in the problem) then you will be done and you just have to do simple algebra of multiplying/dividing and adding/subtracting and so on and so forth.
hey Randy once you isolate the radicals you square both sides. The side with only the radical is not foiled bu the side that contains a radical and exponent or number will be foiled
okay so I understand what to do with square roots and all but what happens/what are you supposed to do if you have the third root of something in a solving for "x" equation?
For the problem that Mrs. Johnson gave us: (square root 18+square root 3)(square root 15+ square root 2), I got 2 times square root of 30+ 4+ 3 times square root 5 + square root 6 as my answer. Is that right?
Andy, you would set both sides to the 1/3 power, isolate x, and solve with algebra
Cube both sides. :)
thank you as well Christian!
Thanks bestfriend!/You're Welcome bestfriend!
oh yeah Archanas right Andy, you cube both sides. i was thinking it was set to the third power. my bad.
Stuck on review problem 4, part b. I know you have to isolate the radicals and square both sides but I can't get the right answer. I may be foiling the square roots wrong but I'm not completely sure where I'm making a mistake
so i solved the problem: 2x+(square root x-2) = x
and i ended up with 4(square root x-2) = x-2
how do i reduce this further? do i divide both sides by 4? or what?
how do you find the vertices...I'm confused!
For #1 on the ellipses worksheet, is the foci located at (-1, -3+root 12) and (-1, -3-root 12)? I just want to make sure I'm doing this right.
Yeah Archana thats what I got to. I think I'm doing it right at least! But I was wondering if anyone knew how to find the equation from the vertices and foci
The vertices are the two end points of the major axis.
Hmm, for #6 problems on the ellipse w.s. how would you figure out the X-radius, I got the Y-r from subtracting out from the center, but im not sure how you would figure out the x-r, am i forgetting something?
The best way to do #6 on the elipse worksheet, the best way to solve is to graph it and use that.
What you need to do is find the center by using the two vertices and plotting, then going directly in the middle of the two. For #6 the center is 1,1. Then you know the y-radius from looking at the graph and the vertices distance from the center. It is 4, so you square that to get 16 for the denominator. Lastly, plot the foci, and find their length by looking at it. The foci are 3 in length. From this you know that root 16 - root x-radidus = 3 square or 9. So that means the x-radius = root 7
Hope I helped
So on #7 you would get 7 for the radii, and -1,4 for the center. So when you take the foci that are 4 from the center, the y denominator would be 49 and the x would be what? I;m getting stuck on how you figure out the x denominator
For numbers 6 and 7 on the ellipse worksheet, I get how you could use the foci to get the x and y radii, but how do you know which numbers to use as the denominators and which to use as the numerators?
Zach: I think you got your denominators mixed up. The major axis is the x axis, so the number given to you in the problem is your x denominator, which is 49. From there, just plug in that same 49 into the foci equation. set your equation up for the foci as major radius squared minus minor radius squared (all under a radical) = Foci (basically the amount of numbers the foci is away from the center). that should give you the y denominator.
Kayla: the numerators are the center. for example, if the center were 1, -2 you would put (x-1)^2 and (y+2)^2 as the numerators.
the denominators are the major and minor radii. for example, if one radii were 49 you would put 49 on the denominator or 7^2. but 7 would be your actual radius, if that makes sense.
how do you find the foci, asymptotes and center of 18 on page 486?
Mrs. Johnson teaches math at Metea Valley High School in Aurora, IL.
Ap Ab Calculus
H Algebra 2 Trig
H Pre Calculus
Regular Pre Calculus