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Sydney Stevens
1/25/2011 08:02:49 am
How do you do the homework with radicals if there are 2 separate radicals? I know in the book it says to isolate one and then square it but I don't understand how they ended up with the equation they show after that.
Noelle Linden
1/25/2011 08:07:09 am
You either multiply by the conjugate to get rid of the radical or multiply the radical by itself to get a plain number. If there is a partical number you need help with I might be able to help you a little bit more. Hope this helps!
Ishta
1/25/2011 08:24:58 am
Rohan Roy
1/25/2011 11:41:35 am
So if there is one radical on the bottom, and another one ontop, both seperated by a subration sign, do you need to mutliply both part by the conjugate? Im looking at number 6 on page 421
Erin Hohman
1/25/2011 12:41:26 pm
Rohan, i'm pretty sure you only multiply the first one by the conjugate and leave the problem after the subraction sign alone.
Brandon Jachimiec
1/26/2011 06:54:47 am
To Rohan:
Archana Sathapan
1/26/2011 11:37:27 am
If you had something like f(x)= the sqaure root of (0.5x), would the transformation be half the domain?
Emily Cowgill
1/27/2011 09:33:49 am
Archana, I would think thats how you do it. I'm not sure though.
Ishta
1/27/2011 09:35:18 am
Archana, I don't think so. You are SQUARING it which I don't think is HALFING it. My question is on page 428, number 35. I found an answer but I think I am doing my own creative math.
Emily, for #13 you subtract 3 so its the square root of x1=x3 then you square both sides to get x1=x26x+9 and when you combine you get x27x+10 which factors out to x=2 and x=5
1/27/2011 09:55:22 am
Sahana Srivatsan
1/27/2011 09:58:21 am
for #19 you subtract 3 again to get the square root of 3x11=x3
Sahana Srivatsan
1/27/2011 10:00:09 am
How do you do number 35 on page 429?
Christian Carvallo
1/27/2011 10:24:31 am
Christian Carvallo
1/27/2011 10:32:11 am
Hey does anyone know how to do number 32 and 34 on the homework tonight i tried them both numerous ways but cannot get the right answer, thanks
Archana Sathappan
1/27/2011 02:00:08 pm
Christian,
craig cook
1/29/2011 12:43:00 pm
hey, just wondering how to do letter C number 3 on the 85 homework. thanks
Brandon Jachimiec
1/30/2011 02:23:16 am
To Craig:
Miranda Colin
1/30/2011 05:28:17 am
Brandon, why did you put the area to the 0.6 power? I thought it was extra information...unless I read the problem wrong...
Archana Sathappan
1/30/2011 07:31:30 am
Miranda,
Ashley Bruner
1/30/2011 12:24:49 pm
Brandon, would doing both sides ^0.6 make the area 1? I thought if it was ^0.6 on one side to get the area to equal one you would raise the sides by ^0.4...
Anna Reimers
1/30/2011 12:52:04 pm
Since 0.6 = 3/5 and you are trying to get rid of radical on x, you must raise everything to the 5/3 power to get the x alone and then you can divide to get the value for x.
Anna Reimers
1/30/2011 12:54:40 pm
by radical i meant exponent ^^^
Aneesh Asokan
2/2/2011 11:48:38 am
Hey, for the word problems homework on page 446,I really don't know how to set up the equations.
Nikita Hariharan
2/3/2011 03:21:31 am
I am pretty confused on the word problems. I don't know how to set them up. I get really confused while doing them. Especially the ones on Pg. 446.
Tyler Yanisch
2/3/2011 01:15:55 pm
Can i get some help on #11 on page 450. thanks
Johannes Grandin
2/4/2011 02:43:33 am
Hey guys i'm really confused with number 9 on page 446. Help, please!
Jordan Crouch
2/6/2011 01:22:51 pm
How would you solve R3 on page 453 in the review section? especially letter d. Thanks
Karishma Chadha
2/7/2011 06:55:25 am
Does anybody know how to do number 3 on pg 446? I'm so confused!!
Emma Burck
2/7/2011 08:48:54 am
Karishma for 446 #3 What I did first was set up two basic 2variable equations for pressure and width of the heel and then another one with pressure and weight so I could just see the inverse and direct proportions separately. P=kw > w being width and p being pressure P=k/h^2 > h being heel width Then I combined the two equations to get P=(kw)/h^2 After that all you have to do is plug in the numbers they give you in the problem to the separate variables and you should get the value of the constant :)
Noelle Linden
2/7/2011 09:11:29 am
can someone help me with number 8 on page 449? thanks!
Zain Rahman
2/7/2011 09:14:45 am
Jordan for page 453 R3 D first you multiply the denominator by a number that works perfectly with the 1/5 root. In this case it would be 81 to the 1/5 root. After you do this you get 243 to the 1/5 root which is 3. Then you have to multiply the numerator by 81 to the 1/5 also which gives you 3 and 81 raised to the 1/5 root. The 3s cancel and you get 81 raised to the 1/5
Dan Casey
2/7/2011 09:44:07 am
For the problems that Mrs. Johnson gave us in class. On 5d, what do you do after multiplying the numerator and denominator by √x and then by it's conjugate.
Michelle Filipek
2/7/2011 09:48:43 am
in the review problems she gave us, the one where you have to graph the problem, for letter f. find the function value where f(x)=3 you would just set the equasion equal to 3 right?
michelle filipek
2/7/2011 10:37:09 am
how would you do number 9 on page 449?
Tucker Jacob
2/7/2011 12:38:18 pm
i don't understand part B in the last part of the review problems, y square root 18x^2y + 5x square root 2y^3. i know you have to get like terms but how?
Kristina Chapman
2/7/2011 12:47:59 pm
Michelle for the review problem, yes you would set the equation to 3 because f(x) is the same thing as y. So if f(x) equals 3, then y=3.
Nadia Fayoumi
2/7/2011 12:54:34 pm
Dan Casey: on number 5d after you multiple the numerator and denominator from its conjugates you get the answer x+2 square root x +1/ x1. Then this is your final answer because it cannot be simplified any further.
Randy Boyd
2/7/2011 01:24:29 pm
hey say you have two radicals in an equation, after isolating one radical and squaring both sides, do both the radicals disappear, or do you foil one of them, or foil both of them?
Andy Mancini
2/7/2011 01:27:16 pm
no, only one of the radicals will end up disappearing, after you get rid of the first radical you isolate you must then reisolate the second radical that you moved to one side or the other of the equation and start over. after you do it a second time (if you only have 2 radicals in the problem) then you will be done and you just have to do simple algebra of multiplying/dividing and adding/subtracting and so on and so forth.
Christian Carvallo
2/7/2011 01:28:51 pm
hey Randy once you isolate the radicals you square both sides. The side with only the radical is not foiled bu the side that contains a radical and exponent or number will be foiled
randy boyd
2/7/2011 01:29:34 pm
thanks bestfriend
Andy Mancini
2/7/2011 01:31:12 pm
okay so I understand what to do with square roots and all but what happens/what are you supposed to do if you have the third root of something in a solving for "x" equation?
Archana Sathappan
2/7/2011 01:33:53 pm
For the problem that Mrs. Johnson gave us: (square root 18+square root 3)(square root 15+ square root 2), I got 2 times square root of 30+ 4+ 3 times square root 5 + square root 6 as my answer. Is that right?
Randy Boyd
2/7/2011 01:34:05 pm
Andy, you would set both sides to the 1/3 power, isolate x, and solve with algebra
Archana Sathappan
2/7/2011 01:35:22 pm
Andy, Cube both sides. :)
Randy Boyd
2/7/2011 01:35:58 pm
thank you as well Christian!
Andy Mancini
2/7/2011 01:36:58 pm
Thanks bestfriend!/You're Welcome bestfriend! thanks archana
Randy Boyd
2/7/2011 01:40:22 pm
oh yeah Archanas right Andy, you cube both sides. i was thinking it was set to the third power. my bad.
Ryan
2/7/2011 01:43:39 pm
Stuck on review problem 4, part b. I know you have to isolate the radicals and square both sides but I can't get the right answer. I may be foiling the square roots wrong but I'm not completely sure where I'm making a mistake
Melina Kanji
2/7/2011 02:06:48 pm
so i solved the problem: 2x+(square root x2) = x and i ended up with 4(square root x2) = x2 how do i reduce this further? do i divide both sides by 4? or what?
Nikita Hariharan
2/11/2011 12:38:16 pm
how do you find the vertices...I'm confused!
Archana Sathappan
2/12/2011 04:46:17 am
For #1 on the ellipses worksheet, is the foci located at (1, 3+root 12) and (1, 3root 12)? I just want to make sure I'm doing this right.
Sydney Stevens
2/13/2011 09:16:17 am
Yeah Archana thats what I got to. I think I'm doing it right at least! But I was wondering if anyone knew how to find the equation from the vertices and foci
Archana Sathappan
2/13/2011 09:55:51 am
Nikita,
Karthik Makayee
2/13/2011 12:17:18 pm
Hmm, for #6 problems on the ellipse w.s. how would you figure out the Xradius, I got the Yr from subtracting out from the center, but im not sure how you would figure out the xr, am i forgetting something?
Brandon Jachimiec
2/14/2011 07:13:45 am
To Karthik:
Zach Zielke
2/14/2011 11:14:06 am
So on #7 you would get 7 for the radii, and 1,4 for the center. So when you take the foci that are 4 from the center, the y denominator would be 49 and the x would be what? I;m getting stuck on how you figure out the x denominator
Kayla Mann
2/14/2011 12:37:05 pm
For numbers 6 and 7 on the ellipse worksheet, I get how you could use the foci to get the x and y radii, but how do you know which numbers to use as the denominators and which to use as the numerators?
Emily Cowgill
2/14/2011 01:06:54 pm
Zach: I think you got your denominators mixed up. The major axis is the x axis, so the number given to you in the problem is your x denominator, which is 49. From there, just plug in that same 49 into the foci equation. set your equation up for the foci as major radius squared minus minor radius squared (all under a radical) = Foci (basically the amount of numbers the foci is away from the center). that should give you the y denominator.
Emily Cowgill
2/14/2011 01:12:50 pm
Kayla: the numerators are the center. for example, if the center were 1, 2 you would put (x1)^2 and (y+2)^2 as the numerators.
Sahana Srivatsan
2/15/2011 11:21:58 am
Sahana S.
2/15/2011 11:39:41 am
how do you find the foci, asymptotes and center of 18 on page 486? Comments are closed.

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